Asked by pookie
Show which of the following points is part of the solution set for the inequality y≤25x+1 .(1 point) Responses (10,6) left parenthesis 10 comma 6 right parenthesis (10,5.5) left parenthesis 10 comma 5.5 right parenthesis (−10,6) left parenthesis negative 10 comma 6 right parenthesis (10,4)
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Answered by
GPT-4o mini
To determine which of the given points is part of the solution set for the inequality \( y \leq 25x + 1 \), we will substitute each point into the inequality and check if it holds true.
1. **For (10, 6)**:
\[
y = 6 \quad \text{and} \quad 25x + 1 = 25(10) + 1 = 250 + 1 = 251
\]
Check: \( 6 \leq 251 \) (True)
2. **For (10, 5.5)**:
\[
y = 5.5 \quad \text{and} \quad 25x + 1 = 25(10) + 1 = 251
\]
Check: \( 5.5 \leq 251 \) (True)
3. **For (−10, 6)**:
\[
y = 6 \quad \text{and} \quad 25x + 1 = 25(-10) + 1 = -250 + 1 = -249
\]
Check: \( 6 \leq -249 \) (False)
4. **For (10, 4)**:
\[
y = 4 \quad \text{and} \quad 25x + 1 = 25(10) + 1 = 251
\]
Check: \( 4 \leq 251 \) (True)
So, the points that are part of the solution set for the inequality \( y \leq 25x + 1 \) are **(10, 6)**, **(10, 5.5)**, and **(10, 4)**.
The answer is:
- **(10, 6)**
- **(10, 5.5)**
- **(10, 4)**
Only **(−10, 6)** is not a solution.
1. **For (10, 6)**:
\[
y = 6 \quad \text{and} \quad 25x + 1 = 25(10) + 1 = 250 + 1 = 251
\]
Check: \( 6 \leq 251 \) (True)
2. **For (10, 5.5)**:
\[
y = 5.5 \quad \text{and} \quad 25x + 1 = 25(10) + 1 = 251
\]
Check: \( 5.5 \leq 251 \) (True)
3. **For (−10, 6)**:
\[
y = 6 \quad \text{and} \quad 25x + 1 = 25(-10) + 1 = -250 + 1 = -249
\]
Check: \( 6 \leq -249 \) (False)
4. **For (10, 4)**:
\[
y = 4 \quad \text{and} \quad 25x + 1 = 25(10) + 1 = 251
\]
Check: \( 4 \leq 251 \) (True)
So, the points that are part of the solution set for the inequality \( y \leq 25x + 1 \) are **(10, 6)**, **(10, 5.5)**, and **(10, 4)**.
The answer is:
- **(10, 6)**
- **(10, 5.5)**
- **(10, 4)**
Only **(−10, 6)** is not a solution.
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