To determine which of the given points satisfies the inequality \( y \leq 25x + 1 \), we need to substitute the x-value of each point into the equation \( y = 25x + 1 \) and see if the corresponding y-value is less than or equal to the calculated value.
-
For the point (10, 5.5):
- \( x = 10 \)
- Calculate \( y = 25(10) + 1 = 250 + 1 = 251 \)
- Check: \( 5.5 \leq 251 \) (True)
-
For the point (10, 6):
- \( x = 10 \)
- Calculate \( y = 25(10) + 1 = 250 + 1 = 251 \)
- Check: \( 6 \leq 251 \) (True)
-
For the point (10, 4):
- \( x = 10 \)
- Calculate \( y = 25(10) + 1 = 250 + 1 = 251 \)
- Check: \( 4 \leq 251 \) (True)
-
For the point (−10, 6):
- \( x = -10 \)
- Calculate \( y = 25(-10) + 1 = -250 + 1 = -249 \)
- Check: \( 6 \leq -249 \) (False)
Based on this analysis, all points except for (−10, 6) satisfy the inequality \( y \leq 25x + 1 \). Therefore, the points that are part of the solution set are (10, 5.5), (10, 6), and (10, 4).