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Show, using the properties of limits, that if lim x-->5 f(x)=3 then lim x---->5 x^2-4/f(x)=7

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limit of quotient is quotient of limits, so we have

lim(x->5) x^2-4 = 25-4 = 21
lim(x->5) f(x) = 3

21/3 = 7

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