The reaction between ethyl methyl ketone and peroxyacetic acid results in the formation of a peroxy acid intermediate, which then undergoes a nucleophilic attack by the ketone. This leads to the formation of a cyclic intermediate which rearranges to form the final products.
The reaction mechanism is as follows:
1. Peroxyacetic acid (CH3CO3H) reacts with ethyl methyl ketone (C4H8O) to form an acyloxy radical intermediate.
2. The acyloxy radical intermediate undergoes a nucleophilic attack by the ketone to form a cyclic intermediate.
3. The cyclic intermediate then rearranges to form the final products, which are acetic acid (CH3COOH) and a ketone compound.
Therefore, the products formed in this reaction are acetic acid and a ketone compound.
Show the reaction mechanism of the reaction below and name the products formed.
Ethyl methyl ketone + peroxyacetic acid-----> ??
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