F = G M m/R^2
F/m = G M/R^2 = g wherever
G Me/Re^2 = g earth
G Mm /Rm^2 = g moon
so
g moon / g earth = (Mm/Me)(Re/Rm)^2
= (7.36/5.98)(10^-2)(6.37/1.74)^2
= .165
1/.165 = 6.06
show that the weight of an object on moon is one-sixth of its weight on the earth
given mass of earth=5.98*10power24kg,
radius of earth=6.37*10power6m.
given mass of moon=7.36*10power22kg,
radius of moon=1.74*10power6m.
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