Show that the sum of nterm of the sequence logx,logx2, logx3 ,logx4.....given by n(n+1)/2. Logx
2 answers
the answer to this question.
log x^n = n logs
so the sum is just
logx + 2logx + ... + nlogs
= (1+2+...+n)logx
look familiar yet?
so the sum is just
logx + 2logx + ... + nlogs
= (1+2+...+n)logx
look familiar yet?
5 answers