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Show that the sine or cosine value of an angle measuring 48 degree is equivalent to the sine or cosine value of that same angle...Asked by mei x yuzu
Show that the sine or cosine value of an angle measuring 48° is equivalent to the sine or cosine value of that same angle measured in radians and state the value of the function.
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GPT-4o mini
To show that the sine or cosine value of an angle measuring 48° is equivalent to the sine or cosine value of that same angle in radians, we first need to convert 48 degrees to radians.
The conversion formula from degrees to radians is:
\[
\text{radians} = \text{degrees} \times \frac{\pi}{180}
\]
For 48 degrees, we have:
\[
48^\circ \times \frac{\pi}{180} = \frac{48\pi}{180}
\]
This simplifies to:
\[
\frac{48\pi}{180} = \frac{8\pi}{30} = \frac{4\pi}{15}
\]
Now we can confirm that the sine and cosine functions give the same numerical values in both degrees and radians:
1. **Sine Function**:
\[
\sin(48^\circ) = \sin\left(\frac{4\pi}{15}\right)
\]
2. **Cosine Function**:
\[
\cos(48^\circ) = \cos\left(\frac{4\pi}{15}\right)
\]
Now, we can calculate the sine and cosine values.
Using a calculator (or trigonometric tables):
- \(\sin(48^\circ) \approx 0.7431\)
- \(\cos(48^\circ) \approx 0.6691\)
Since \(\sin\) and \(\cos\) functions only depend on the angle, the values calculated for \(\sin\left(\frac{4\pi}{15}\right)\) and \(\cos\left(\frac{4\pi}{15}\right)\) will be the same as those from \(48^\circ\).
Thus:
- \(\sin\left(\frac{4\pi}{15}\right) \approx 0.7431\)
- \(\cos\left(\frac{4\pi}{15}\right) \approx 0.6691\)
Therefore, we have shown that \( \sin(48^\circ) = \sin\left(\frac{4\pi}{15}\right) \) and \( \cos(48^\circ) = \cos\left(\frac{4\pi}{15}\right) \) with the numerical values approximately equal to:
- \( \sin(48^\circ) \approx 0.7431 \)
- \( \cos(48^\circ) \approx 0.6691 \)
The conversion formula from degrees to radians is:
\[
\text{radians} = \text{degrees} \times \frac{\pi}{180}
\]
For 48 degrees, we have:
\[
48^\circ \times \frac{\pi}{180} = \frac{48\pi}{180}
\]
This simplifies to:
\[
\frac{48\pi}{180} = \frac{8\pi}{30} = \frac{4\pi}{15}
\]
Now we can confirm that the sine and cosine functions give the same numerical values in both degrees and radians:
1. **Sine Function**:
\[
\sin(48^\circ) = \sin\left(\frac{4\pi}{15}\right)
\]
2. **Cosine Function**:
\[
\cos(48^\circ) = \cos\left(\frac{4\pi}{15}\right)
\]
Now, we can calculate the sine and cosine values.
Using a calculator (or trigonometric tables):
- \(\sin(48^\circ) \approx 0.7431\)
- \(\cos(48^\circ) \approx 0.6691\)
Since \(\sin\) and \(\cos\) functions only depend on the angle, the values calculated for \(\sin\left(\frac{4\pi}{15}\right)\) and \(\cos\left(\frac{4\pi}{15}\right)\) will be the same as those from \(48^\circ\).
Thus:
- \(\sin\left(\frac{4\pi}{15}\right) \approx 0.7431\)
- \(\cos\left(\frac{4\pi}{15}\right) \approx 0.6691\)
Therefore, we have shown that \( \sin(48^\circ) = \sin\left(\frac{4\pi}{15}\right) \) and \( \cos(48^\circ) = \cos\left(\frac{4\pi}{15}\right) \) with the numerical values approximately equal to:
- \( \sin(48^\circ) \approx 0.7431 \)
- \( \cos(48^\circ) \approx 0.6691 \)
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