Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Show that the sine or cosine value of an angle measuring 48 degree is equivalent to the sine or cosine value of that same angle...Question
Show that the sine or cosine value of an angle measuring 48° is equivalent to the sine or cosine value of that same angle measured in radians and state the value of the function.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To show that the sine or cosine value of an angle measuring \( 48^\circ \) is equivalent to the sine or cosine value of that same angle measured in radians, we first need to convert \( 48^\circ \) to radians.
The conversion from degrees to radians is given by the formula:
\[
\text{radians} = \text{degrees} \times \frac{\pi}{180}
\]
For \( 48^\circ \):
\[
48^\circ = 48 \times \frac{\pi}{180} = \frac{48\pi}{180} = \frac{48\pi}{180} = \frac{8\pi}{30} = \frac{4\pi}{15}
\]
Now we have:
- \( 48^\circ \) in degrees is equivalent to \( \frac{4\pi}{15} \) in radians.
Next, we can express the sine and cosine values:
1. **Sine:**
\[
\sin(48^\circ) = \sin\left(\frac{4\pi}{15}\right)
\]
2. **Cosine:**
\[
\cos(48^\circ) = \cos\left(\frac{4\pi}{15}\right)
\]
At this stage, we do not have to calculate the numerical values of these sine and cosine functions. Both expressions \( \sin(48^\circ) \) and \( \sin\left(\frac{4\pi}{15}\right) \) represent the same value, and likewise for the cosine.
To provide the numerical value for either function, we can calculate:
- Using a calculator:
- \( \sin(48^\circ) \approx 0.7431 \)
- \( \cos(48^\circ) \approx 0.6691 \)
- Or, with radians:
- \( \sin\left(\frac{4\pi}{15}\right) \approx 0.7431 \)
- \( \cos\left(\frac{4\pi}{15}\right) \approx 0.6691 \)
In conclusion, we have shown that:
\[
\sin(48^\circ) = \sin\left(\frac{4\pi}{15}\right)
\]
and
\[
\cos(48^\circ) = \cos\left(\frac{4\pi}{15}\right)
\]
Both values are approximately:
\[
\sin(48^\circ) \approx 0.7431
\]
\[
\cos(48^\circ) \approx 0.6691
\]
The conversion from degrees to radians is given by the formula:
\[
\text{radians} = \text{degrees} \times \frac{\pi}{180}
\]
For \( 48^\circ \):
\[
48^\circ = 48 \times \frac{\pi}{180} = \frac{48\pi}{180} = \frac{48\pi}{180} = \frac{8\pi}{30} = \frac{4\pi}{15}
\]
Now we have:
- \( 48^\circ \) in degrees is equivalent to \( \frac{4\pi}{15} \) in radians.
Next, we can express the sine and cosine values:
1. **Sine:**
\[
\sin(48^\circ) = \sin\left(\frac{4\pi}{15}\right)
\]
2. **Cosine:**
\[
\cos(48^\circ) = \cos\left(\frac{4\pi}{15}\right)
\]
At this stage, we do not have to calculate the numerical values of these sine and cosine functions. Both expressions \( \sin(48^\circ) \) and \( \sin\left(\frac{4\pi}{15}\right) \) represent the same value, and likewise for the cosine.
To provide the numerical value for either function, we can calculate:
- Using a calculator:
- \( \sin(48^\circ) \approx 0.7431 \)
- \( \cos(48^\circ) \approx 0.6691 \)
- Or, with radians:
- \( \sin\left(\frac{4\pi}{15}\right) \approx 0.7431 \)
- \( \cos\left(\frac{4\pi}{15}\right) \approx 0.6691 \)
In conclusion, we have shown that:
\[
\sin(48^\circ) = \sin\left(\frac{4\pi}{15}\right)
\]
and
\[
\cos(48^\circ) = \cos\left(\frac{4\pi}{15}\right)
\]
Both values are approximately:
\[
\sin(48^\circ) \approx 0.7431
\]
\[
\cos(48^\circ) \approx 0.6691
\]
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.