Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Show that the distance between the points (x,y) and the line Ax + By + C = 0 is: D = (Ax + By + C) / sqrt(A^2 + B^2) So, would...Asked by Zach
Show that the distance between the points (x,y) and the line Ax + By + C = 0 is:
D = (Ax + By + C) / sqrt(A^2 + B^2)
So, would you start out by multiplying sqrt (A^2 + B^2) to both sides and then it would become:
sqrt (A^2 + B^2)D = Ax + By + C
Then square both sides,
D^2(A^2 + B^2) = (Ax + By + C)^2
Then I got lost, could someone direct me through this problem? Did I start out the right way? Thanks!
Answers
Answered by
drwls
Just manipulating the equation for D will not constitute a proof that it is correct. You need to derive it somehow.
Try deriving an equation for a line through (x,y) that is perpendicular to the line Ax + By +C = 0. Then compute where the two lines intersect. Call that point (x', y'). Then compute the distance between (x,y) and (x',y').
A proof can be found here:
http://mathworld.wolfram.com/Point-LineDistance2-Dimensional.html
Try deriving an equation for a line through (x,y) that is perpendicular to the line Ax + By +C = 0. Then compute where the two lines intersect. Call that point (x', y'). Then compute the distance between (x,y) and (x',y').
A proof can be found here:
http://mathworld.wolfram.com/Point-LineDistance2-Dimensional.html
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.