cosΞΈ = (x-2)/3
sinΞΈ = (y-4)/3
since sin^2ΞΈ + cos^2ΞΈ = 1,
(x-2)^2/9 + (y-4)^2/9 = 1
Now just expand that out to get your x-y equation
Show that the cartesian equation of the curve that has the parameter π=π+ππππππ½ and π=π+ππππππ½ is ππ+ππβππβππ+ππ=π.
1 answer