To solve the equation \(3x^2 = 21\), we start by dividing both sides by 3:
\[ x^2 = \frac{21}{3} = 7 \]
Now, we take the square root of both sides:
\[ x = \pm \sqrt{7} \]
This gives us two solutions:
\[ x = \sqrt{7} \quad \text{and} \quad x = -\sqrt{7} \]
Since there are two distinct values of \(x\) that satisfy the equation, the solution set contains:
two solutions.