To solve the equation \(3x^2 = 21\), we can start by dividing both sides by 3:
\[ x^2 = 7 \]
Now we take the square root of both sides:
\[ x = \pm \sqrt{7} \]
This indicates that there are two solutions: \( \sqrt{7} \) and \( -\sqrt{7} \).
Therefore, the number of solutions in the solution set for the equation \(3x^2 = 21\) is two.