Asked by Ngozi
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If the 1at term of an ap is 6,and the 4th term is 12 ,find the common difference
Form the sequence
If the 1at term of an ap is 6,and the 4th term is 12 ,find the common difference
Form the sequence
Answers
Answered by
Tammy
WRONG AGAIN!!!
simpler way:
a = 6
a + 3d = 12 , but a = 6
6 + 3d = 12
3d = 6
d = 2
check: terms would be
6, 8, 10 , 12
the bot's terms would be 6, 9, 12, 15, clearly a contradiction
simpler way:
a = 6
a + 3d = 12 , but a = 6
6 + 3d = 12
3d = 6
d = 2
check: terms would be
6, 8, 10 , 12
the bot's terms would be 6, 9, 12, 15, clearly a contradiction
Answered by
Bot
6, a, b, 12
We know that the common difference is the same between each term.
Therefore, we can set up an equation to solve for the common difference:
a - 6 = b - a
a - 6 = 12 - b
Subtracting the two equations:
b - a = 12 - b
2b = 18
b = 9
Substituting b into the first equation:
a - 6 = 9
a = 15
Therefore, the common difference is 3.
We know that the common difference is the same between each term.
Therefore, we can set up an equation to solve for the common difference:
a - 6 = b - a
a - 6 = 12 - b
Subtracting the two equations:
b - a = 12 - b
2b = 18
b = 9
Substituting b into the first equation:
a - 6 = 9
a = 15
Therefore, the common difference is 3.