Question

Shelia, Jason, Jamarla, and Shaka each found the percent of 15 out of 25. Circle the method
that most closely matches how you would solve the problem.
Shelia's Method
15 ÷ 25 = 0.6
0.6 is
101
Lo is equivalent to 10o
Jason's Method Do the other three methods make sense mathematically? Why or
why not?
15 out of 25 is equivalent to 60% out of 100%.
Jamarla's Method
x = 15
100
25 x 4 = 100, so 15 × 4 = x. x = 60
60%
Shaka's Method
15 ÷ 25 = 0.6
0.6 × 100 = 60 60%

Answer 1

Let's evaluate each method used by Shelia, Jason, Jamarla, and Shaka to find the percent of 15 out of 25, and identify which looks most mathematically sound.

### Shelia's Method
Sheila calculates:
- \(15 ÷ 25 = 0.6\)
- Then incorrectly states that \(0.6\) is equivalent to \(101\) (possibly a typo).
- She implies a faulty conversion, as \(0.6\) should correctly be converted to \(60\%\), not \(101\).

**Evaluation**: Sheila's method is flawed due to the incorrect understanding of converting decimals to percentages.

### Jason's Method
Jason states:
- \(15\) out of \(25\) gives the equivalent fraction \(60\%\) out of \(100\%\).

**Evaluation**: Jason's method is valid, since he correctly interprets the proportion of \(15\) out of \(25\) to the equivalent of \(60\%\).

### Jamarla's Method
Jamarla writes:
- Setting \(x = 15\) (not clear, but seems to represent a percent situation).
- \(100\) relates to \(25\) multiplied by \(4\) which gives \(100\).
- Then calculates \(15 × 4 = x\), finding that \(x = 60\%\).

**Evaluation**: Jamarla's method is valid. She employs cross-multiplication to solve for \(x\) effectively, leading to the correct percentage \(60\%\).

### Shaka's Method
Shaka calculates:
- \(15 ÷ 25 = 0.6\)
- Then correctly states \(0.6 × 100 = 60\%\).

**Evaluation**: Shaka's method is accurate, as he uses the decimal to percent conversion correctly.

### Final Summary
The methods that make sense mathematically are Jason, Jamarla, and Shaka's methods. Shelia's method is flawed due to an incorrect conversion and misunderstanding of percentages.

The method that most closely matches how I would solve the problem would be Shaka's method since it explicitly converts the decimal to a percentage in one clear step.