shavonne is decorating a wreath that has an outer diameter of 22 in. and an inner diameter of 18 in. what is the maximum area of the wreath that she can cover with decorations?

1 answer

To find the maximum area of the wreath that Shavonne can cover with decorations, we need to calculate the area of the circular ring formed by the outer and inner diameters.

  1. Calculate the outer radius: \[ \text{Outer radius} = \frac{\text{Outer diameter}}{2} = \frac{22 , \text{in}}{2} = 11 , \text{in} \]

  2. Calculate the inner radius: \[ \text{Inner radius} = \frac{\text{Inner diameter}}{2} = \frac{18 , \text{in}}{2} = 9 , \text{in} \]

  3. Calculate the area of the outer circle: \[ \text{Area of outer circle} = \pi \times (\text{Outer radius})^2 = \pi \times (11 , \text{in})^2 = \pi \times 121 , \text{in}^2 = 121\pi , \text{in}^2 \]

  4. Calculate the area of the inner circle: \[ \text{Area of inner circle} = \pi \times (\text{Inner radius})^2 = \pi \times (9 , \text{in})^2 = \pi \times 81 , \text{in}^2 = 81\pi , \text{in}^2 \]

  5. Calculate the area of the wreath (the area of the ring): \[ \text{Area of the wreath} = \text{Area of outer circle} - \text{Area of inner circle} = 121\pi , \text{in}^2 - 81\pi , \text{in}^2 = (121 - 81)\pi , \text{in}^2 = 40\pi , \text{in}^2 \]

  6. Final Area Calculation: \[ \text{Area of the wreath} \approx 40 \times 3.14 \approx 125.6 , \text{in}^2 \]

So, the maximum area of the wreath that Shavonne can cover with decorations is approximately \( 40\pi , \text{in}^2 \) or about \( 125.6 , \text{in}^2 \).