sgr2 sinD cosD=sinD

Answer 1

If you're trying to solve

sqrt(2) sinD cosD = sinD

sinD(sqrt(2) cosD - 1) = 0

sinD = 0 means that D=0 + k*pi for any integer k will work.

cosD = 1/√2 means that D=2k*pi ± pi/4 will also work.

Answer 2

So:

47
137
227
317

Do I need to add +360n?