f-7 = 5(s-7)
f+14 = 2(s+14)
father = 42
son = 14
check:
42-7 = 35 = 5(14-7) ✅
42+14 = 56 = 2(14+14) ✅
Seven years back the age of a father was 5 times the age of his son. It will be twice after 14 years. Find their present age.
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2 answers