let's choose the consonants and vowels first
No of combinations
= C(5,2) x C(2,1) = 10(2) = 20
Since you titled your post "permutations" we now want to arrange these.
That can be done in 6 ways each
So the number of permutations is 6(20) = 120
Seven cards, each marked a letter can be arranged to spell NUMBERS. how many three letter code words can be formed with 2 consonants and one vowel?
Thanks 😁
1 answer