To be in A intersect B, a number must be both prime and a factor of 36
factors of 36 less than 16:
1 3 4 6 9 12
of those only 1 and 3 are prime
unite those with the multiples of 4
which are 4 8 12
and you get
1 3 4 8 12
Sets A,B and C are subsets of U.
U= positive integers less than 16
A= prime numbers
B= factors of 36
C= multiples of 4
(A intersect B)' union C {?}
My answer:
1,4,5,6,7,8,9,10,11,12,13,14,15 union 4,8,12
{4,8,12}
1 answer
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