Set up a Hess's law cycle, and use the following information to calculate ÄH°f for aqueous nitric acid, HNO3(aq). You will need to use fractional coefficients for some equations.
3 NO2(g) + H2O(l) 2 HNO3(aq) + NO(g) ÄH° = -138.4 kJ
2 NO(g) + O2(g) 2 NO2(g) ÄH° = -114 kJ
4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(l) ÄH° = -1169.6 kJ
NH3(g) ÄH°f = -46.1 kJ/mol
H2O(l)
2 answers
Where does the H2O(l) by itself at the bottom of your post fit in?
the h2o is
ÄH°f = -285.8 kJ/mol
ÄH°f = -285.8 kJ/mol