Set the following settings on the Simulation. Starch: 3 Amylase: 0 Temp: 35 Maltose: 0 Maltase: 3 pH: 7 Glucose: 0 Amylase Inhibitor: 0 Question 4 What did you observe?(1 point) Responses Starch was denatured Starch was denatured Starch was not broken down by the maltose enzyme Starch was not broken down by the maltose enzyme Glucose was present Glucose was present Starch was broken down by the maltose enzyme

Answer 1

Given the settings you've provided for the simulation, here is an analysis of the scenario:

• Starch is present at a concentration of 3.
• Amylase, which breaks down starch into maltose, is set to 0.
• Maltase, which breaks down maltose into glucose, is set to 3.
• Temperature is at 35 (which is typically within the optimal range for enzyme activity).
• pH is 7, which is also generally optimal for enzyme activity.
• Maltose and glucose are both set to 0.
• There is no amylase inhibitor.

Based on these conditions:

• Since there is no amylase present, starch cannot be broken down into maltose. Without maltose, maltase will not have a substrate to act upon, and thus will not produce any glucose.

Given these observations, the most accurate response would be: Starch was not broken down by the maltose enzyme.

This response indicates that starch remained intact due to the absence of amylase, preventing it from being converted into maltose, which is necessary for the maltase enzyme to produce glucose.