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series -12288,3072,-768,x,-48 find x
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Sure looks like we are dividing a term by -4 to get to the next one,
so .....
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2. find the next three terms of the sequence.
-6, -24, -96, -384 1) -768, -1536 , -3072 2) -768, -3072, -12288 3) -1536, -6144 ,
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what are the next 3 terms?
12288, 3072 768 192
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What are the next three terms in the sequence 12288, 3072, 768, 192?
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Represent the function f(x)=10ln(8-x) as a Maclaurin series.
sum_{n=0}^infty (c_n) (x^n) The coefficients are C_0= 10ln8
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