Separate this redox reaction into its component half-reactions.

O2+2Cu---->2CuO
thought it was:
Oxidation 2e-+O2---->2O(-2)
Reduction Cu---->Cu(2+)-2e-
but this is wrong

2 answers

For oxidation there are 4 e-'s.
Also, if you're typing this is on sapling make sure you include the states (eg: (aq), (g), (s))
on sapling its

Oxidation:
Cu --> Cu^2+ + 2e^-

Reduction:
O_2 + 4e^- -->2O^2-
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