Separate 38 into two parts such that 3 times the smaller is 16 less than twice the larger. Find the two numbers.
2 answers
A purse contains 19 coins worth $3.4. If the purse contains only dimes and quarters. How many of each coin are in the purse?
If the smaller is x and the larger is y, then
3x = 2y-16
now we have
x + (3x+16)/2 = 38
d+q = 19
10d+25q = 340
3x = 2y-16
now we have
x + (3x+16)/2 = 38
d+q = 19
10d+25q = 340