Question

select two values for x that would make `8+2x\le20` true.
Answer
another
Answer
another
Answer
another includeing 10 8 or 6 4
Answered by GPT-4o mini
To solve the inequality \( 8 + 2x \leq 20 \), we first isolate \( x \).

1. Subtract 8 from both sides:
\[
2x \leq 20 - 8
\]
\[
2x \leq 12
\]

2. Divide both sides by 2:
\[
x \leq 6
\]

Now, any value of \( x \) that is less than or equal to 6 will satisfy the inequality.

Here are two example values for \( x \):
- \( x = 0 \)
- \( x = 5 \)

Both values satisfy the inequality \( 8 + 2x \leq 20 \):
- For \( x = 0 \):
\[
8 + 2(0) = 8 \leq 20 \quad \text{(True)}
\]
- For \( x = 5 \):
\[
8 + 2(5) = 18 \leq 20 \quad \text{(True)}
\]

Thus, two valid values for \( x \) are **0** and **5**.
Answered by GPT-4o mini
Sure! We can choose different values for \( x \) that still satisfy the inequality \( 8 + 2x \leq 20 \) (or \( x \leq 6 \)).

Here are two more example values:

- \( x = 3 \)
- \( x = 6 \)

Let's check both:

1. For \( x = 3 \):
\[
8 + 2(3) = 8 + 6 = 14 \leq 20 \quad \text{(True)}
\]

2. For \( x = 6 \):
\[
8 + 2(6) = 8 + 12 = 20 \leq 20 \quad \text{(True)}
\]

Both values \( 3 \) and \( 6 \) satisfy the inequality \( 8 + 2x \leq 20 \).

So, two additional valid values for \( x \) are **3** and **6**.
Answered by GPT-4o mini
Certainly! Here are two more values for \( x \) that satisfy the inequality \( 8 + 2x \leq 20 \) (or \( x \leq 6 \)):

- \( x = 1 \)
- \( x = 4 \)

Let's verify both:

1. For \( x = 1 \):
\[
8 + 2(1) = 8 + 2 = 10 \leq 20 \quad \text{(True)}
\]

2. For \( x = 4 \):
\[
8 + 2(4) = 8 + 8 = 16 \leq 20 \quad \text{(True)}
\]

Both values \( 1 \) and \( 4 \) satisfy the inequality \( 8 + 2x \leq 20 \).

So, two additional valid values for \( x \) are **1** and **4**.
Answered by GPT-4o mini
To clarify, the inequality \(8 + 2x \leq 20\) simplifies to \(x \leq 6\). Thus, any values of \(x\) that are less than or equal to 6 will satisfy the inequality.

Given that, we can include the values **4** and **6** (which you mentioned) as well as others:

1. **\( x = 6 \)**:
\[
8 + 2(6) = 8 + 12 = 20 \leq 20 \quad \text{(True)}
\]

2. **\( x = 4 \)**:
\[
8 + 2(4) = 8 + 8 = 16 \leq 20 \quad \text{(True)}
\]

So, \(4\) and \(6\) are two values that satisfy the inequality.

For additional values without violating the constraint, consider:

3. **\( x = 0 \)**:
\[
8 + 2(0) = 8 \leq 20 \quad \text{(True)}
\]

4. **\( x = 2 \)**:
\[
8 + 2(2) = 8 + 4 = 12 \leq 20 \quad \text{(True)}
\]

To summarize:
- Values **4** and **6** satisfy \(8 + 2x \leq 20\).
- Additional values could be **0** and **2**.