To solve the inequality \( 8 + 2x \leq 20 \), we can first isolate \( 2x \):
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Subtract 8 from both sides: \[ 2x \leq 20 - 8 \] \[ 2x \leq 12 \]
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Divide both sides by 2: \[ x \leq 6 \]
Now, we need to find values of \( x \) that satisfy \( x \leq 6 \).
The available options are:
- 10
- 8
- 6
- 4
From these options:
- 10 is not less than or equal to 6.
- 8 is not less than or equal to 6.
- 6 is equal to 6.
- 4 is less than 6.
Therefore, the values that make \( 8 + 2x \leq 20 \) true are 6 and 4.