The probability of the heart in your example would be 13/50 if the king or ace did not include a heart.
You have still not included probability that either/both a king or ace will be a heart. Thus the probability of the heart in your next equations would be either 12/50 or 11/50.
Either-or probabilities are found by adding the individual probabilities.
Add the probabilities of the three equations.
Select three different five card combinations or five-card hands from your favorite card game that utilizes a standard 52-card deck containing four suits (clubs, hearts, diamonds, and spades), with each suit containing 13 cards with numbers 2-10 and face cards ace, king, queen, and jack. Then, do the following.
Using the concept of dependent probabilities, determine the odds that you would draw these hands (card combinations) directly from a deck of cards.
Determine the probability that you would not draw these hands (card combinations) directly from a deck of cards.
This is what I got for the first part and I feel it's wrong. Didn't work on the second part yet.
Statistics - Shasha, Thursday, May 25, 2017 at 10:40pm
When looking at the possibilities of drawing 5 cards from a deck of 52 there are going to be 2,598,960 possibilities. Now if we are looking to pull 2 kings, a heart, and 2 10’s, it would be 4/52, 3/51, 4/50, 4/49, 3/48 = (4*3*4*4*3/52*51*50*49*48) = The probabilities these cards would be pulled in a five-card combination is 576/ 311,875,200 =1/541,450 or 1.86E-06
Here is the answer I got, am I on the right track?
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