The three characteristics of proportional relationships on a graph are:
a. the points will form a straight line
c. it passes through the origin (0,0)
e. the ratio of y/x is the same for all points on the line
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select three characteristics of proportional relationships on a graph.
a. the points will form a straight line
b. the x values are always larger than the y values
c. it passes through the origin (0,0).
d. the y values are always larger than the x values
e. the ratio of y/x is the same for all points on the line
f.
g.
11 answers
The three characteristics of proportional relationships on a graph are:
a. the points will form a straight line
c. it passes through the origin (0,0)
e. the ratio of y/x is the same for all points on the line
To determine the unit price for each soda in the packs, we can divide the total price by the number of sodas in each package.
6-pack for $2.99: \[ \text{Unit Price} = \frac{\text{Total Price}}{\text{Number of Sodas}} = \frac{2.99}{6} \approx 0.4983 \] Rounding to the hundredths place, the unit price is $0.50 per soda.
12-pack for $3.99: \[ \text{Unit Price} = \frac{3.99}{12} \approx 0.3325 \] Rounding to the hundredths place, the unit price is $0.33 per soda.
Thus, the answers are:
To find the unit price for the 24-pack:
24-pack for $5.99: \[ \text{Unit Price} = \frac{\text{Total Price}}{\text{Number of Sodas}} = \frac{5.99}{24} \approx 0.2496 \] Rounding to the hundredths place, the unit price is $0.25 per soda.
Now, we can summarize the unit prices we calculated earlier:
Now, comparing the unit prices:
The package with the best unit price is b. 24-pack at $0.25 per soda.
To determine the constant of proportionality between distance \( (d) \) and time \( (t) \), we can use the values from the table. The constant of proportionality (k) can be calculated as follows:
\[ k = \frac{d}{t} \]
Let's calculate \( k \) using one of the pairs from the table:
Using the first row:
\[ k = \frac{5 \text{ miles}}{62.5 \text{ minutes}} = 0.08 \text{ miles per minute} \]
Now let's verify that this constant holds for the other pairs:
For the second row:
For the third row:
Thus, the constant of proportionality is: \[ \text{Constant of Proportionality} = 0.08 \text{ miles per minute} \]
Now, to select the appropriate equation to model the relationship between distance and time, we need an equation that represents this direct proportionality:
We know that: \[ d = k \cdot t \quad \text{where} , k = 0.08 \] So, we get: \[ d = 0.08t \]
Therefore, the correct equation is: d. \( d = 0.08t \).
To simplify the expression \((x + 1) - (-2x - 5)\), we first distribute the negative sign in front of the parentheses:
\[ (x + 1) - (-2x - 5) = (x + 1) + (2x + 5) \]
Now, we can combine the like terms:
Combine the \(x\) terms: \[ x + 2x = 3x \]
Combine the constant terms: \[ 1 + 5 = 6 \]
Putting these together, we have:
\[ 3x + 6 \]
Thus, the simplified expression is:
\[ \boxed{3x + 6} \]
To solve the equation \( \frac{2}{5}(x + 15) = 26 \), we can follow these steps:
To eliminate the fraction, we can multiply both sides of the equation by \(5\):
\[ 5 \cdot \left(\frac{2}{5}(x + 15)\right) = 5 \cdot 26 \]
This simplifies to:
\[ 2(x + 15) = 130 \]
Now, distribute the \(2\) on the left side:
\[ 2x + 30 = 130 \]
Next, we need to isolate the term with \(x\). We can do this by subtracting \(30\) from both sides:
\[ 2x + 30 - 30 = 130 - 30 \]
This simplifies to:
\[ 2x = 100 \]
Now, divide both sides by \(2\) to solve for \(x\):
\[ x = \frac{100}{2} \]
This simplifies to:
\[ x = 50 \]
The value of \(x\) is:
\[ \boxed{50} \]
To verify, we can substitute \(x = 50\) back into the original equation:
\[ \frac{2}{5}(50 + 15) = 26 \]
Calculating inside the parentheses:
\[ \frac{2}{5}(65) = 26 \]
Calculating the left side:
\[ \frac{130}{5} = 26 \]
Since both sides are equal, our solution \(x = 50\) is verified.