To solve the expression \((2x+2)−(3x+11)\), we first simplify it step by step:
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Distribute the minus sign across the second parenthesis: \[ (2x + 2) - (3x + 11) = 2x + 2 - 3x - 11 \]
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Combine like terms: \[ (2x - 3x) + (2 - 11) = -x - 9 \]
Now we need to identify which of the given responses is equivalent to \(-x - 9\).
Let's check each response:
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\(2x - 3x + 2 - 11\): \[ 2x - 3x + 2 - 11 = -x + 2 - 11 = -x - 9 \quad \text{(equivalent)} \]
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\(5x + 9\): \[ \text{Not equivalent} \]
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\(-x - 9\): \[ \text{Clearly equivalent} \]
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\(-x + 9\): \[ \text{Not equivalent} \]
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\(2x - 3x + 2 + 11\): \[ 2x - 3x + 2 + 11 = -x + 2 + 11 = -x + 13 \quad \text{(not equivalent)} \]
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\(5x + 13\): \[ \text{Not equivalent} \]
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\(-x + 13\): \[ \text{Not equivalent} \]
Thus, the two correct equivalent expressions to \((2x+2)−(3x+11)\) are:
- \(2x - 3x + 2 - 11\)
- \(-x - 9\)
The two expressions that are equivalent to the given expression are:
- \(2x - 3x + 2 - 11\)
- \(-x - 9\)
1 answer