To determine which points are part of the solution set for the inequality \( y \leq 25x + 1 \), we need to check each point by substituting the x-value into the equation \( y = 25x + 1 \) and comparing y-values.
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For the point \( (10, 4) \):
- \( y = 25(10) + 1 = 250 + 1 = 251 \)
- \( 4 \leq 251 \) is true.
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For the point \( (10, 5.5) \):
- \( y = 25(10) + 1 = 250 + 1 = 251 \)
- \( 5.5 \leq 251 \) is true.
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For the point \( (10, 6) \):
- \( y = 25(10) + 1 = 250 + 1 = 251 \)
- \( 6 \leq 251 \) is true.
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For the point \( (5, 3) \):
- \( y = 25(5) + 1 = 125 + 1 = 126 \)
- \( 3 \leq 126 \) is true.
All points are part of the solution set for the inequality \( y \leq 25x + 1 \).
The points that are part of the solution set are:
- \( (10, 4) \)
- \( (10, 5.5) \)
- \( (10, 6) \)
- \( (5, 3) \)