Select the points that are part of the solution set for the inequality y≤25x+1 . Select ALL that apply.(2 points) Responses (10, 5.5) (10, 5.5) (10, 4) (10, 4) (5, 3) (5, 3) (10, 6) (10, 6)

Answer 1

To determine which points are part of the solution set for the inequality \( y \leq 25x + 1 \), we need to check each point to see if it satisfies the inequality.

1. For the point \( (10, 5.5) \):

   • Substitute \( x = 10 \) into the inequality:
     \( y \leq 25(10) + 1 \)
     \( y \leq 250 + 1 \)
     \( y \leq 251 \)
     Since \( 5.5 \leq 251 \) is true, this point is part of the solution set.

2. For the point \( (10, 4) \):

   • Substitute \( x = 10 \):
     \( y \leq 25(10) + 1 \)
     We already calculated that \( y \leq 251 \).
     Since \( 4 \leq 251 \) is true, this point is part of the solution set.

3. For the point \( (5, 3) \):

   • Substitute \( x = 5 \):
     \( y \leq 25(5) + 1 \)
     \( y \leq 125 + 1 \)
     \( y \leq 126 \)
     Since \( 3 \leq 126 \) is true, this point is part of the solution set.

4. For the point \( (10, 6) \):

   • Substitute \( x = 10 \):
     \( y \leq 25(10) + 1 \)
     Again, \( y \leq 251 \).
     Since \( 6 \leq 251 \) is true, this point is part of the solution set.

In summary, all points meet the condition set by the inequality \( y \leq 25x + 1 \).

The solution set includes:

• (10, 5.5)
• (10, 4)
• (5, 3)
• (10, 6)

So, all four points are part of the solution set for the given inequality.