To determine which points satisfy the inequality \( y \leq 25x + 1 \), we need to evaluate each given point by substituting its coordinates into the inequality.
Let's evaluate each point:
-
For the point (5, 3):
- Substitute: \( y = 3 \), \( x = 5 \)
- Check: \( 3 \leq 25(5) + 1 \)
- Calculate: \( 3 \leq 125 + 1 \) → \( 3 \leq 126 \) (True)
-
For the point (10, 5.5):
- Substitute: \( y = 5.5 \), \( x = 10 \)
- Check: \( 5.5 \leq 25(10) + 1 \)
- Calculate: \( 5.5 \leq 250 + 1 \) → \( 5.5 \leq 251 \) (True)
-
For the point (10, 6):
- Substitute: \( y = 6 \), \( x = 10 \)
- Check: \( 6 \leq 25(10) + 1 \)
- Calculate: \( 6 \leq 250 + 1 \) → \( 6 \leq 251 \) (True)
-
For the point (10, 4):
- Substitute: \( y = 4 \), \( x = 10 \)
- Check: \( 4 \leq 25(10) + 1 \)
- Calculate: \( 4 \leq 250 + 1 \) → \( 4 \leq 251 \) (True)
Since all calculations are true, all the points provided satisfy the inequality \( y \leq 25x + 1 \).
The solution set includes all points:
- (5, 3)
- (10, 5.5)
- (10, 6)
- (10, 4)