To determine which ordered pair is part of the solution set for the equation \( y = 4x + 2 \), we can substitute \( x = 3 \) into the equation and solve for \( y \):
\[ y = 4(3) + 2 \] \[ y = 12 + 2 \] \[ y = 14 \]
Now we can check the ordered pairs:
- \( (3, 7) \): \( y \neq 14 \) (not a solution)
- \( (3, 14) \): \( y = 14 \) (is a solution)
- \( (3, 45) \): \( y \neq 14 \) (not a solution)
- \( (3, 12) \): \( y \neq 14 \) (not a solution)
The correct response is:
(3, 14)