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Select the operation that should be done to both sides of the equation to solve for the value of x.(4 points)

add both sides subtract both sides multiply both sides divide both sides
x + 15 = -23

x15
= 7

-5x = 40

x - 23 = 49

3 answers

To solve for \( x \) in each of the given equations, you would perform the following operations on both sides:

  1. Equation: \( x + 15 = -23 \)
    Operation: Subtract both sides
    Solution: \( x = -23 - 15 \)
    Result: \( x = -38 \)

  2. Equation: \( \frac{x}{15} = 7 \)
    Operation: Multiply both sides
    Solution: \( x = 7 \times 15 \)
    Result: \( x = 105 \)

  3. Equation: \( -5x = 40 \)
    Operation: Divide both sides
    Solution: \( x = \frac{40}{-5} \)
    Result: \( x = -8 \)

  4. Equation: \( x - 23 = 49 \)
    Operation: Add both sides
    Solution: \( x = 49 + 23 \)
    Result: \( x = 72 \)

In summary, the operations needed for each equation are:

  1. Subtract both sides
  2. Multiply both sides
  3. Divide both sides
  4. Add both sides
r u sure

Yes, I’m sure about the operations stated to solve for \( x \) in each of the given equations. Let's break them down step by step again:

  1. \( x + 15 = -23 \)

    • To solve for \( x \), you need to isolate \( x \). So you subtract 15 from both sides:
    • Operation: Subtract both sides
    • Result: \( x = -23 - 15 \)
    • Result: \( x = -38 \)

  2. \( \frac{x}{15} = 7 \)

    • To solve for \( x \), you want to eliminate the fraction by multiplying both sides by 15:
    • Operation: Multiply both sides
    • Result: \( x = 7 \times 15 \)
    • Result: \( x = 105 \)

  3. \( -5x = 40 \)

    • To solve for \( x \), you need to isolate \( x \) by dividing both sides by -5:
    • Operation: Divide both sides
    • Result: \( x = \frac{40}{-5} \)
    • Result: \( x = -8 \)

  4. \( x - 23 = 49 \)

    • To solve for \( x \), you need to isolate \( x \) by adding 23 to both sides:
    • Operation: Add both sides
    • Result: \( x = 49 + 23 \)
    • Result: \( x = 72 \)

The operations listed in my previous response are correct for solving each of the equations. If there is a specific part you’d like to discuss further or if you have any more questions about it, please let me know!