Select the equation that solves this problem:
Eight coins (dimes and quarters) are worth 170 cents. How many dimes are
there?
a. 10d + 25(11 - d) = 170
b. 10d + 25(8 - d) = 170
c. 10d + 5(8 - d) = 60
d. 10d + 5(11 - d) = 60
3 answers
So what do you think?
I send to you solution for simmilar problem.
A quarters is worth 25 cents and a dime is worth 10 cents.
q = numbers of a quarters
d = numbers of a dimes
q + d = 8
q = 8 - d
Value of money :
10 ¢ * d + 25 ¢ * q = 170 ¢
10 d + 25 q = 170
10 d + 25 ( 8 - d ) = 170
Equation b.
10 d + 25 ( 8 - d ) = 170
10 d + 25 * 8 + 25 * ( - d ) = 170
10 d + 200 - 25 d = 170
10 d - 25 d = 170 - 200
- 15 d = - 30 Divide both sides by - 15
d = - 30 / - 15
d = 2
q = 8 - d = 8 - 2 = 6
2 dimes and 6 quarters
2 * 10 ¢ + 6 * 25 ¢ =
20 ¢ + 150 ¢ = 170 ¢
q = numbers of a quarters
d = numbers of a dimes
q + d = 8
q = 8 - d
Value of money :
10 ¢ * d + 25 ¢ * q = 170 ¢
10 d + 25 q = 170
10 d + 25 ( 8 - d ) = 170
Equation b.
10 d + 25 ( 8 - d ) = 170
10 d + 25 * 8 + 25 * ( - d ) = 170
10 d + 200 - 25 d = 170
10 d - 25 d = 170 - 200
- 15 d = - 30 Divide both sides by - 15
d = - 30 / - 15
d = 2
q = 8 - d = 8 - 2 = 6
2 dimes and 6 quarters
2 * 10 ¢ + 6 * 25 ¢ =
20 ¢ + 150 ¢ = 170 ¢
1 answer