To determine which equation has infinitely many solutions, we need to simplify each equation and see if they lead to a true statement regardless of the value of \( x \) (indicating infinitely many solutions).
Option A: \( 3x + 5 = 3x - 5 \)
Subtract \( 3x \) from both sides:
\( 5 = -5 \)
This is a false statement, so there are no solutions.
Option B: \( 3 - 3x = -3(x - 1) \)
Distribute on the right side:
\( 3 - 3x = -3x + 3 \)
Add \( 3x \) to both sides:
\( 3 = 3 \)
This is a true statement, so there are infinitely many solutions.
Option C: \( 4x + 1 = 4(x + 1) \)
Distribute on the right side:
\( 4x + 1 = 4x + 4 \)
Subtract \( 4x \) from both sides:
\( 1 = 4 \)
This is a false statement, so there are no solutions.
Option D: \( 3x = 2x + 1 \)
Subtract \( 2x \) from both sides:
\( x = 1 \)
This has a single solution.
Therefore, the equation that has infinitely many solutions is Option B: \( 3 - 3x = -3(x - 1) \).