To simplify the expression \((2^{-\sqrt{}})^3 \cdot 2^{-\frac{1}{2}}\), we can use the properties of exponents.
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First, simplify \((2^{-\sqrt{}})^3\):
\[
(2^{-\sqrt{}})^3 = 2^{-3\sqrt{}}
\]
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Now, combine this with the second part of the expression:
\[
2^{-3\sqrt{}} \cdot 2^{-\frac{1}{2}} = 2^{-3\sqrt{} - \frac{1}{2}}
\]
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We keep the exponent as is because we cannot further simplify without knowing the value of \(\sqrt{}\). However, we can check if our result corresponds to one of the answer choices in a general form or by testing rational values.
Unfortunately, none of the responses clearly correlate to \(2^{-3\sqrt{} - \frac{1}{2}}\) without further simplification.
To explore the responses:
- \(2^{\frac{1}{2}}\) means the square root of 2.
- \(2^{2}\) means 4.
- \(2\) is also just 2.
From this input, it seems we need the approximation or numerical value of \(-3\sqrt{} - \frac{1}{2}\). Since we cannot give an explicit numerical value without knowing what \( \sqrt{} \) is standing for, but, in a common context such as if \(\sqrt{} = 1\), none of the standard rational exponents or simple integer interpretations match the options available.
Please clarify if \( \sqrt{} \) is specified, and I can determine if one of the responses correlates correctly!
Otherwise, based on exponent simplification:
\[
2^{-3\sqrt{} - \frac{1}{2}}
\]
But if you consider \(-\sqrt{} = -1\), leading to:
\[
2^{-3 - \frac{1}{2}} = 2^{-\frac{7}{2}} = \frac{1}{2^{\frac{7}{2}}} = 2^{-3.5}
\]
Which would be the opposing of direct options.
Solution confirmed: \(2^{-3\sqrt{} - \frac{1}{2}}\) as described, unless clarification directs.