Select the choice that indicates AB←→ is the perpendicular bisector of CD←→ if they intersect at P .(1 point)

Question

Responses

AB¯¯¯¯¯¯¯¯⊥CD¯¯¯¯¯¯¯¯ and CP¯¯¯¯¯¯¯¯≅DP¯¯¯¯¯¯¯¯
Modifying above upper A upper B with bar perpendicular to Modifying above upper C upper D with bar and Modifying above upper C upper P with bar congruent to Modifying above upper D upper P with bar

AC¯¯¯¯¯¯¯¯⊥BD¯¯¯¯¯¯¯¯ and AP¯¯¯¯¯¯¯¯≅BP¯¯¯¯¯¯¯¯
Modifying above upper A upper C with bar perpendicular to Modifying above upper B upper D with bar and Modifying above upper A upper P with bar congruent to Modifying above upper B upper P with bar

AP¯¯¯¯¯¯¯¯≅BP¯¯¯¯¯¯¯¯
Modifying above upper A upper P with bar congruent to Modifying above upper B upper P with bar

CD¯¯¯¯¯¯¯¯⊥AB¯¯¯¯¯¯¯¯

Answer 1

The correct choice that indicates \( AB \) is the perpendicular bisector of \( CD \) if they intersect at \( P \) is:

AB⊥CD and CP≅DP

This means that line segment \( AB \) is perpendicular to line segment \( CD \), and the lengths of segments \( CP \) and \( DP \) are equal, confirming that \( P \) is the midpoint of \( CD \).