Select the choice that indicates AB←→ is the perpendicular bisector of CD←→ if they intersect at P .

3 answers

For \( AB \) to be the perpendicular bisector of \( CD \), the following must be true:

  1. \( P \) is the midpoint of \( CD \).
  2. \( AB \) intersects \( CD \) at \( P \).
  3. \( AB \) is perpendicular to \( CD \) at \( P \).

Therefore, if you are given a choice indicating these three criteria, that would be the one that identifies \( AB \) as the perpendicular bisector of \( CD \) at the point \( P \). If you have specific choices listed, please provide them for further assistance.

You should provide what the answer choices are.
But it should be CD ⊥ AB and CP≅DP

Given the information that \( AB \) is the perpendicular bisector of \( CD \) and they intersect at \( P \), the correct choice would be:

\( CD \perp AB \) and \( CP \cong DP \)

This means:

  1. \( CD \perp AB \) indicates that \( AB \) is perpendicular to \( CD \).
  2. \( CP \cong DP \) indicates that point \( P \) is the midpoint of segment \( CD \), meaning \( CP \) is congruent to \( DP \).

Both conditions together confirm that \( AB \) is indeed the perpendicular bisector of \( CD \).