f(x) = -2(x^2-x) + 6
= -2(x^2 - x + 1/4) + 6 + 2(1/4)
= -2(x - 1/2)^2 + 13/2
f(x)=0 when
(x - 1/2)^2 = 13/4
x = (1±√13)/2
. . .
Select the approximate values of x that are solutions to f(x) = 0, where
f(x) = -2x2 + 2x + 6
answers available, which one is correct?
{–1.30, 2.30}
{-2, 2}
{–1.00, –3.00}
{–0.33, 0.33}
1 answer