To determine which of the provided options is equivalent to \( \frac{0.\overline{63}}{1} \) of a mile, we first need to convert \( 0.\overline{63} \) into a fraction.
Let \( x = 0.\overline{63} \).
To eliminate the repeating decimal, we can multiply \( x \) by 100:
\[ 100x = 63.\overline{63} \]
Now, we can subtract the first equation from the second:
\[ 100x - x = 63.\overline{63} - 0.\overline{63} \]
This simplifies to:
\[ 99x = 63 \]
Now, solving for \( x \):
\[ x = \frac{63}{99} \]
We can simplify \( \frac{63}{99} \) by finding the greatest common divisor (GCD) of 63 and 99, which is 9:
\[ x = \frac{63 \div 9}{99 \div 9} = \frac{7}{11} \]
Now we know \( 0.\overline{63} = \frac{7}{11} \).
Let’s compare this value to the options given:
A. \( \frac{9}{7} \) — Not equal to \( \frac{7}{11} \)
B. \( \frac{7}{11} \) — Equal to \( \frac{7}{11} \)
C. \( \frac{9}{11} \) — Not equal to \( \frac{7}{11} \)
D. \( \frac{7}{9} \) — Not equal to \( \frac{7}{11} \)
E. \( \frac{63}{100} \) — Not equal to \( \frac{7}{11} \)
F. \( \frac{21}{33} \) — Can be simplified:
\[ \frac{21 \div 3}{33 \div 3} = \frac{7}{11} \]
Thus, the correct answers are:
B. \( \frac{7}{11} \)
F. \( \frac{21}{33} \)