To determine which expressions are equivalent to the original algebraic expression \((3x−8)+(2x+5)−(4x−8)\), let's simplify it step by step.
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Start with the original expression: \[ (3x - 8) + (2x + 5) - (4x - 8) \]
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Distributing the negative sign across \(-(4x - 8)\): \[ = (3x - 8) + (2x + 5) - 4x + 8 \]
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Combine like terms:
- Combine \(3x + 2x - 4x\): \[ 3x + 2x - 4x = x \]
- Combine constants \(-8 + 5 + 8\): \[ -8 + 5 + 8 = -8 + 5 + 8 = -8 + 13 = 5 \]
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The expression simplifies to: \[ x + 5 \]
Now, let's review the provided responses to identify which expressions are equivalent to \(x + 5\):
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\(3x−8+2x+5−4x−8\)
- Equivalent (This simplifies to \(x + 5\) as worked out above).
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\(3x−8+2x+5−4x+8\)
- Not Equivalent (This simplifies to \(x + 13\)).
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\(3x+2x−4x−8+5+8\)
- Equivalent (This simplifies to \(x + 5\)).
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\(5x−4x−8+5+8\)
- Equivalent (This simplifies to \(x + 5\)).
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\(x−8+5+8\)
- Equivalent (This simplifies to \(x + 5\)).
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\(x−13+8\)
- Not Equivalent (This simplifies to \(x - 5\)).
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\(x−3+8\)
- Not Equivalent (This simplifies to \(x + 5\)).
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\(x−21\)
- Not Equivalent (This simplifies to \(x - 21\)).
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\(x+5\)
- Equivalent (This is exactly what we simplified to).
So, the expressions that are equivalent to the original expression \( (3x−8)+(2x+5)−(4x−8) \) are:
- \(3x−8+2x+5−4x−8\)
- \(3x+2x−4x−8+5+8\)
- \(5x−4x−8+5+8\)
- \(x−8+5+8\)
- \(x+5\)
Thus, the equivalent expressions are:
- \(3x−8+2x+5−4x−8\)
- \(3x+2x−4x−8+5+8\)
- \(5x−4x−8+5+8\)
- \(x−8+5+8\)
- \(x+5\)