Select all equations that have

Question

as a solution. x=3
A
x+7=10x+7=10x+7=10
B
3+x=33+x=33+x=3
C
x⋅3=1x\cdot 3=1x⋅3=1
D
4⋅x=124\cdot x=124⋅x=12

Answer 1

To determine which of the equations has \( x = 3 \) as a solution, we will substitute \( x = 3 \) into each equation and see if it satisfies them.

A. \( x + 7 = 10 \)

Substituting \( x = 3 \): \[ 3 + 7 = 10 \ 10 = 10 \quad \text{(True)} \]

B. \( 3 + x = 3 \)

Substituting \( x = 3 \): \[ 3 + 3 = 3 \ 6 = 3 \quad \text{(False)} \]

C. \( x \cdot 3 = 1 \)

Substituting \( x = 3 \): \[ 3 \cdot 3 = 1 \ 9 = 1 \quad \text{(False)} \]

D. \( 4 \cdot x = 12 \)

Substituting \( x = 3 \): \[ 4 \cdot 3 = 12 \ 12 = 12 \quad \text{(True)} \]

Thus, the equations that have \( x = 3 \) as a solution are:

• A: \( x + 7 = 10 \)
• D: \( 4 \cdot x = 12 \)