To analyze the system of inequalities given by:
- \( y > -\frac{1}{3}x \)
- \( y < -\frac{1}{3}x - 2 \)
we can break it down as follows:
- The first inequality, \( y > -\frac{1}{3}x \), represents a region above the line \( y = -\frac{1}{3}x \).
- The second inequality, \( y < -\frac{1}{3}x - 2 \), represents a region below the line \( y = -\frac{1}{3}x - 2 \).
Now, consider the slopes of the two lines:
- Both lines have the same slope of \(-\frac{1}{3}\), meaning they are parallel.
- The second line is vertically translated downwards by 2 units compared to the first line, making it impossible for any \( y \) value to simultaneously satisfy both inequalities simultaneously.
Given that there are no points that can satisfy \( y \) being both greater than the first line and less than the second line, we conclude:
D. The system has no solutions.