Sehyr solved the equation w2−7=11 . She seems to have made an error in her work because the solution she found does not work. Observe Sehyr’s work to find her error and correct it to find the solution to the equation.

Sehyr’s work:

w2−7=11

w2−7+7=11+7 Using the Addition Property of Equality

w22=182 Using the Division Property of Equality

w=9

1 answer

Let's look at Sehyr's work step by step to identify the error and find the correct solution.

  1. The original equation is: \[ w^2 - 7 = 11 \]

  2. Sehyr correctly applied the Addition Property of Equality to isolate \(w^2\): \[ w^2 - 7 + 7 = 11 + 7 \rightarrow w^2 = 18 \] Here, she correctly added 7 to both sides of the equation.

  3. However, the subsequent step is where she made an error: \[ w^2 = 18 \] From this point, she incorrectly stated \(w^2\) as \(w^2/2 = 18/2\) and went on to solve for \(w\) as: \[ w = 9 \]

    This is incorrect.

  4. The correct next step after \(w^2 = 18\) is to take the square root of both sides: \[ w = \sqrt{18} \] Since square roots can be both positive and negative, we also have: \[ w = \pm \sqrt{18} \]

  5. Simplifying \(\sqrt{18}\): \[ \sqrt{18} = \sqrt{9 \cdot 2} = \sqrt{9} \cdot \sqrt{2} = 3\sqrt{2} \]

  6. Therefore, the complete solution is: \[ w = 3\sqrt{2} \quad \text{or} \quad w = -3\sqrt{2} \]

In conclusion, the error in Sehyr's work was in the incorrect simplification after isolating \(w^2\). The correct solutions are: \[ w = 3\sqrt{2} \quad \text{and} \quad w = -3\sqrt{2} \]