Sehyr solved the equation w2−7=11

. She seems to have made an error in her work because the solution she found does not work. Observe Sehyr’s work to find her error and correct it to find the solution to the equation.

Sehyr’s work:

w2−7=11


w2−7+7=11+7
Using the Addition Property of Equality

w22=182
Using the Division Property of Equality

w=9

1 answer

Let's analyze Sehyr's work step by step to identify her error and find the correct solution.

She started with the equation:

\[ w^2 - 7 = 11 \]

  1. Adding 7 to both sides:
    Sehyr correctly applied the Addition Property of Equality:

    \[ w^2 - 7 + 7 = 11 + 7 \]
    Simplifying gives:
    \[ w^2 = 18 \]

  2. Here is where the error occurs:
    In her next step, Sehyr incorrectly wrote:

    \[ w^2 = 18 \]
    but improperly wrote \( w^2/2 = 182 \), which is incorrect. The correct step should be to take the square root of both sides.

  3. Taking the square root:
    The correct next step would be:

    \[ w = \pm \sqrt{18} \]

    Simplifying \( \sqrt{18} \) gives:
    \[ \sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2} \]

  4. Final solutions:
    Therefore, the solutions are:

    \[ w = 3\sqrt{2} \quad \text{and} \quad w = -3\sqrt{2} \]

So, Sehyr's error was in handling the equation after adding 7. The correct solutions to the equation \( w^2 - 7 = 11 \) are \( w = 3\sqrt{2} \) and \( w = -3\sqrt{2} \).