The error in Sehyr's work is when she added 7 to both sides of the equation. It should have been subtracted instead. To correct her mistake, the correct step would be:
w/2 - 7 + 7 = 11 + 7 (using the addition property of equality)
w/2 = 18
Then, to solve for w, we can multiply both sides by 2:
2 * (w/2) = 18 * 2 (using the multiplication property of equality)
w = 36
Therefore, the correct solution to the equation is w = 36.
Sehyr solved the equation w/2 - 7= 11 she seems to have made an error in her work because the solution she found does not work. observe sehyrs work to find her error and correct it to fin the solutio n to the equation.
sehyrs work:
w/2- 7+11
w/2-7+7=11+7 (using the addition property of equality)
w/2/2 = 18/2 (using the division property of equality)
w=9
The solution to the equation is __
5 answers
The solution to the equation is __
fill in the blank
fill in the blank
The correct solution to the equation is w = 36.
How many of the following equations have the solution {5}?
2(x-3) + 1 =5
3b/15=1
2h-30=40
The number of equations that have the solution set {5}___
2(x-3) + 1 =5
3b/15=1
2h-30=40
The number of equations that have the solution set {5}___
Let's solve each equation to determine if the solution set is {5}.
1. 2(x-3) + 1 = 5
Expanding and simplifying:
2x - 6 + 1 = 5
2x - 5 = 5
Adding 5 to both sides:
2x = 10
Dividing by 2:
x = 5
The solution to this equation is x = 5.
2. 3b/15 = 1
Multiplying both sides by 15:
3b = 15
Dividing by 3:
b = 5
The solution to this equation is b = 5.
3. 2h - 30 = 40
Adding 30 to both sides:
2h = 70
Dividing by 2:
h = 35
The solution to this equation is h = 35.
Out of the three equations, only the first one (2(x-3) + 1 = 5) has the solution set {5}. Therefore, the number of equations that have the solution set {5} is 1.
1. 2(x-3) + 1 = 5
Expanding and simplifying:
2x - 6 + 1 = 5
2x - 5 = 5
Adding 5 to both sides:
2x = 10
Dividing by 2:
x = 5
The solution to this equation is x = 5.
2. 3b/15 = 1
Multiplying both sides by 15:
3b = 15
Dividing by 3:
b = 5
The solution to this equation is b = 5.
3. 2h - 30 = 40
Adding 30 to both sides:
2h = 70
Dividing by 2:
h = 35
The solution to this equation is h = 35.
Out of the three equations, only the first one (2(x-3) + 1 = 5) has the solution set {5}. Therefore, the number of equations that have the solution set {5} is 1.