(a) For Sidewalk 1, using points (2, 7) and (0, 3):
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Find the slope (m):
\( m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 7}{0 - 2} = \frac{-4}{-2} = 2 \) -
Use point-slope form:
\( y - 7 = 2(x - 2) \)
Expand:
\( y = 2x + 3 \)Equation: \( y = 2x + 3 \)
(b) For Sidewalk 2, using points (1, 5) and (3, 3):
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Find the slope (m):
\( m = \frac{3 - 5}{3 - 1} = \frac{-2}{2} = -1 \) -
Use point-slope form:
\( y - 5 = -1(x - 1) \)
Expand:
\( y = -x + 6 \)Equation in slope-intercept form: \( y = -x + 6 \)
(c) The system of equations is consistent and independent because the slopes are different (2 and -1), meaning they intersect at one point.
(d) To find the point of intersection, set the equations equal:
\( 2x + 3 = -x + 6 \)
\( 2x + x = 6 - 3 \)
\( 3x = 3 \)
\( x = 1 \)
Now substitute \( x = 1 \) back into either equation to get \( y \):
Using \( y = 2x + 3 \):
\( y = 2(1) + 3 = 5 \)
Coordinates of intersection: \( (1, 5) \)