Scientific Notation Online Practice

Question

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Question
A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×105
gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)
Responses

54.78×106
lb.
54.78 times 10 superscript 6 baseline lb.

5.478×106
lb.
5.478 times 10 superscript 6 baseline lb.

5.478×105
lb.
5.478 times 10 superscript 5 baseline lb.

54.78×105
lb.

Answer 1

To find the weight of the water in an Olympic-sized swimming pool, we can use the following calculation:

1. We know that one gallon of water weighs about 8.3 lb.
2. An Olympic-sized swimming pool holds 6.6 × 10^5 gallons.

Now, we calculate the total weight of the water:

\[ \text{Weight} = \text{Volume} \times \text{Weight per gallon} \]

Plugging in the numbers:

\[ \text{Weight} = (6.6 \times 10^5 \text{ gallons}) \times (8.3 \text{ lb/gallon}) \]

Next, we perform the multiplication of the numbers:

\[ 6.6 \times 8.3 = 54.78 \]

Then, we combine this with the power of ten:

\[ \text{Weight} = 54.78 \times 10^5 \text{ lb} \]

To express this in proper scientific notation, we should adjust it to have one digit before the decimal:

\[ 54.78 \times 10^5 \text{ lb} = 5.478 \times 10^6 \text{ lb} \]

Thus, the approximate weight of the water in an Olympic-sized swimming pool, in scientific notation, is:

5.478×10^6 lb.