Sara discarded 1/10 of the apples she picked as defective. Of the apples remaining, 300 were made into cider. The rest were sold as fresh fruit. What fraction of the total apples picked were sold as fresh fruit?(1 point)

Question

Responses

not enough information
not enough information

4/5

3/5

3/10

Answer 1

Let's denote the total number of apples picked as \( x \).

Since Sara discarded \( \frac{1}{10} \) of the apples as defective, the number of defective apples is \( \frac{x}{10} \).

The remaining apples after discarding the defective ones would be:

\[ x - \frac{x}{10} = \frac{10x}{10} - \frac{x}{10} = \frac{9x}{10} \]

Out of the \( \frac{9x}{10} \) remaining apples, it is given that 300 were made into cider. Therefore, the number of apples sold as fresh fruit is:

\[ \frac{9x}{10} - 300 \]

To find the fraction of the total apples picked that were sold as fresh fruit, we need to calculate:

\[ \text{Fresh fruit sold} = \frac{\frac{9x}{10} - 300}{x} \]

This simplifies to:

\[ \text{Fresh fruit sold} = \frac{9x - 3000}{10x} \]

Now we will need to think about when \( \frac{9x - 3000}{10x} \) would be a positive fraction, which means \( 9x - 3000 > 0 \) or \( x > \frac{3000}{9} = 333.33 \). This means any total \( x \geq 334 \) would keep the fresh fruit sold positive.

Assuming \( x = 3400 \) (just an example size that satisfies the inequality), the calculation would look like:

1. Find \( \frac{9 \cdot 3400}{10} = 3060 \).
2. The apples remaining after cider = 3060 - 300 = 2760.
3. The fraction of total fresh fruit sold would be:

\[ \frac{2760}{3400} = \frac{69}{85} \approx 0.8125 \]

Next, let's try with simple values by substituting for \( x \).

Try \( x = 1000 \):

1. Fresh apples = \( \frac{9 \cdot 1000}{10} = 900 \)
2. After cider, we get \( 900 - 300 = 600 \)
3. The fraction sold = \( \frac{600}{1000} = \frac{3}{5} \).

Thus, for the original question, if \( \frac{3}{5} \) of the total apples were sold as fresh fruit, the answer is:

\(\frac{3}{5}\)

Answer 2

The town of Oak Manor measures 3.8 miles by 4.2 miles. Solve for the total area.(1 point)
Responses

15.96 mi2
15.96 mi squared

8 mi2
8 mi squared

16 mi2
16 mi squared

15.96 mi

Answer 3

To find the area of a rectangle, we multiply its length by its width. In this case, the dimensions of Oak Manor are given as 3.8 miles (length) and 4.2 miles (width).

Calculating the area:

\[ \text{Area} = \text{length} \times \text{width} = 3.8 , \text{miles} \times 4.2 , \text{miles} \]

Now, performing the multiplication:

\[ 3.8 \times 4.2 = 15.96 , \text{mi}^2 \]

Thus, the total area of Oak Manor is:

15.96 mi² or 15.96 mi squared (both are correct representations).

So the correct response is either of the following:

• 15.96 mi²
• 15.96 mi squared

Answer 4

A diver searches for a sunken treasure that is 97.2
97.2
feet below the surface. What is the diver's elevation when he is 2/3 of the way down? (1 point)
Responses

−64.8
−
64.8
ft.
negative 64 point 8 ft.

−48.5
−
48.5
ft.
negative 48 point 5 ft.

−145.8 ft.
negative 145 point 8 ft.

−32.4
−
32.4
ft.

Answer 5

To find the diver's elevation when he is \( \frac{2}{3} \) of the way down to the treasure, we first need to calculate how far down that is.

The total depth to the treasure is 97.2 feet.

Calculating \( \frac{2}{3} \) of that depth:

\[ \text{Depth down} = \frac{2}{3} \times 97.2 , \text{ft} \]

Calculating this:

\[ \text{Depth down} = \frac{2 \times 97.2}{3} = \frac{194.4}{3} = 64.8 , \text{ft} \]

Now, since the elevation is below the surface, we will represent it as a negative value:

\[ \text{Diver's elevation} = -64.8 , \text{ft} \]

Thus, the diver's elevation when he is \( \frac{2}{3} \) of the way down is:

−64.8 ft. (or negative 64.8 ft.)